SOLUTION: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.

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Question 43460This question is from textbook 0-07-301602-0
: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. This question is from textbook 0-07-301602-0

Answer by aaaaaaaa(138) About Me  (Show Source):
You can put this solution on YOUR website!
Let's represent the width as w. Therefore, the length is equal to
2w+%2B+2
The perimeter of a rectangle is given by 2w + 2l, and we can equate it to 52, by the problem statement:
2w+%2B+2%282w+%2B+2%29+=+52
Distributive property:
2w+%2B+4w+%2B+4+=+52
6w+%2B+4+=+52
6w+=+52+-+4
6w+=+48
w+=+48%2F6+=+8
Therefore, if width is 8 cm, the length of our rectangle is 2%2A8+%2B+2+=+16+%2B+2+=+18 cm.