Question 394020: The perimeter of rectangle is 30 yards. The width is 12 yards less than twice the length. Find he length and the width of the rectangle.
Answer by pie90010(44)   (Show Source):
You can put this solution on YOUR website! Let L be the length, and L - 12 to be the width
P = 2L + 2W so
W = L - 12
knowing P = 30 we can say
2L + 2(L-12) = 30
then just combine like terms and end up with
4L - 24 = 30
add 34 to both sides
4L = 54
and divide 4 by each side
L = 13.5
BUT WAIT, that is only the length, they also require the width in the question
so simply plug it in, using the first equation
W = 13.5 - 12
W = 1.5
so the complete answer is
L = 13.5
W = 1.5
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