SOLUTION: I need help with the perimeter of a rectangle is 174 inches. The length exceeds the width 37 inches. Find the ninth at the width.
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Question 388572: I need help with the perimeter of a rectangle is 174 inches. The length exceeds the width 37 inches. Find the ninth at the width. Answer by unlockmath(1688) (Show Source):
You can put this solution on YOUR website! Hello,
We can set up the equation as:
x represent the width
x+37 is the length so:
2x+2(x+37)=174
Combine like terms:
4x+74=174
Subtract 74 from both sides and divide by 4 to get:
x=25
There we go the width is 25 inches and the length is 62 inches.
Make sense?
RJ
www.math-unlock.com
