SOLUTION: the length of a rectangle is two less than twice its width.If the perimeter of the rectangle is 44 sq. units what are the dimensions of the rectangle?
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-> SOLUTION: the length of a rectangle is two less than twice its width.If the perimeter of the rectangle is 44 sq. units what are the dimensions of the rectangle?
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Question 384601: the length of a rectangle is two less than twice its width.If the perimeter of the rectangle is 44 sq. units what are the dimensions of the rectangle?
You can put this solution on YOUR website! width = w
length = 2w-2
..
perimeter = 44
..
2*(l+w)=perimeter
2*(w+2w-2)=44
2*(3w-2)=44
6w-4=44
+4 +4
6w=48
/6
w=8 units.
...
Length = 2w-2
2*8-2
=14 units
...
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