SOLUTION: please help me solve this problem: a square poster has two sides measuring 2 ft less than the sides of a square sign. if the difference between their areas is 36sq feet, find the
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-> SOLUTION: please help me solve this problem: a square poster has two sides measuring 2 ft less than the sides of a square sign. if the difference between their areas is 36sq feet, find the
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Question 378786: please help me solve this problem: a square poster has two sides measuring 2 ft less than the sides of a square sign. if the difference between their areas is 36sq feet, find the lengths of the sides of the poster and the sign. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let side of square sign be x
area = x^2
..
square poster side = (x-2)
area = (x-2)^2
..
x^2-(x-2)^2= 36
x^2-(x^2-4x+4)=36
x^2-x^2+4x-4=36
4x-4=36
+4
4x-4+4 = 36+4
4x=40
/4
x= 10 feet. side of sign
10-2=8 feet = side of poster
...
m.ananth@hotmail.ca
