SOLUTION: The perimeter of a rectangle is known to be 88 feet and the area is 363 square feet. Find the dimensions of the rectangle. I need to know how to set this problem up in order to fin

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is known to be 88 feet and the area is 363 square feet. Find the dimensions of the rectangle. I need to know how to set this problem up in order to fin      Log On


   

Question 361782: The perimeter of a rectangle is known to be 88 feet and the area is 363 square feet. Find the dimensions of the rectangle. I need to know how to set this problem up in order to find the answer.
Found 2 solutions by Fombitz, solver91311:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangle is,
P=2L%2B2W=88
1.L%2BW=44
The area of a rectangle is,
A=L%2AW=363
2.LW=363

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


The area of a rectangle is the length times the width.

The perimeter of a rectangle is 2 times the length plus 2 times the width.

Let's use the area formula to develop an expression for length in terms of the width:





Now substitute into the Perimeter formula:



Now multiply through by w:



Put the quadratic in standard form and divide by 2:



Solve for . One root will be the width and the other the length.


John

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