SOLUTION: The length of a rectangle is 20 inches greater than the width and the perimeter is 160 inches. Write an equation and solve for the width of the rectangle. I have tried....

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 20 inches greater than the width and the perimeter is 160 inches. Write an equation and solve for the width of the rectangle. I have tried....       Log On


   

Question 352326: The length of a rectangle is 20 inches greater than the width and the perimeter is 160 inches. Write an equation and solve for the width of the rectangle.

I have tried....
Length times Width divided by heighth
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
P=2W+2L
160=2W+2(W+20)
160=2W+2W+40
160=4W+40
120=4W
W=30 in
W+20=50 in