SOLUTION: A rectangle of has an area of 48 and a perimeter of 32. Find the dimensions of the rectangle.

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Question 350199: A rectangle of has an area of 48 and a perimeter of 32. Find the dimensions of the rectangle.
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
Lw=48
2L+2w=32
.
L+w=16
L=16-w
w(16-w)=48
16w-w^2=48
w^2-16w+48=0
(w-12)(w-4)=0
w=4, L=12
.
Ed