SOLUTION: Please help me solve this :
If an object is thrown vertically upward from the ground with initial speed of 160 feet per second, its height (in feet) t seconds later is given by th
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-> SOLUTION: Please help me solve this :
If an object is thrown vertically upward from the ground with initial speed of 160 feet per second, its height (in feet) t seconds later is given by th
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Question 338864: Please help me solve this :
If an object is thrown vertically upward from the ground with initial speed of 160 feet per second, its height (in feet) t seconds later is given by the function H(t) = -16t^2 + 160t
a) graph the function H(t)
b) use the graph in part a) to determine when the object will hit the ground
c) use the graph in part (a) to estimate how high the object will rise.
I think b) 4 seconds
c) 5 feet
Thank you for sending me correct answer Answer by scott8148(6628) (Show Source):
You can put this solution on YOUR website! the graph is a downward opening parabola
the maximum height is at the vertex , on the axis of symmetry
the general equation for the axis of symmetry is ___ x = -b / (2a)
___ in this case ___ x = -160 / [2(-16)] = 5
H(5) = -16(5^2) + 160(5) = 400
so the max height is 400 ft and it takes 5 sec to get there
time up equals time down , so the "flight" time is 10 sec
