SOLUTION: the preimeter of arectangle is 122inches. The length exceeds the width by 57 inches. find the length and the with?.
the length is?
the width is?
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the length is?
the width is?
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Question 326770: the preimeter of arectangle is 122inches. The length exceeds the width by 57 inches. find the length and the with?.
the length is?
the width is? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let the widtth be x
the length will be x+57
perimeter = 2*(L+W)
2*(x+x+57)=122
2*(2x+57)=122
4x+114=122
add-114 to both sides
4x+114-114=122-114
4x=8
divide by 4
4x/4 = 8/4
x=2 in- the width
length = x+57= 2+57=59in
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