SOLUTION: The length of a rectangle is five more than twice the width. If the perimeter is 70 feet, find the length?
Algebra
->
Rectangles
-> SOLUTION: The length of a rectangle is five more than twice the width. If the perimeter is 70 feet, find the length?
Log On
Geometry: Rectangles
Geometry
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Rectangles
Question 314609
:
The length of a rectangle is five more than twice the width. If the perimeter is 70 feet, find the length?
Answer by
texttutoring(324)
(
Show Source
):
You can
put this solution on YOUR website!
Let l=length and w=width
The formula for perimeter is P=2l+2w and we know that l=2w+5
70=2l+2w
Now replace the l with 2w+5
70=2(2w+5) + 2w
70=4w+10+2w
70=6w+10
60=6w
w=10
l=2w+5
l=2(10)+5
l=25
So the width is 10, and the length is 25.