SOLUTION: The perimeter of a rectangle is 90cm, its width is half its length. What would the equation be to solve this? I think it is 2L+2(1/2L)=90
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Question 313088: The perimeter of a rectangle is 90cm, its width is half its length. What would the equation be to solve this? I think it is 2L+2(1/2L)=90 Answer by J2R2R(94) (Show Source):
You can put this solution on YOUR website! The width of a rectangle is half the length and the perimeter is 90 cm.
Twice the length plus twice the width = 90 cm.
2L + 2(L/2) = 3L = 90 cm.
L = 30 cm.
Therefore we have a rectangle with a length 30 cm and width 15 cm.
This satisfies the criteria.
NB 2L+2(1/2L)=90.
Written 1/2L could mean L/2 or 1/(2L) since the L looks in line with the 2. We know it is supposed to be above the 2 and you meant L/2. It is clearer to write L/2 than 1/2L.
