SOLUTION: Suppose that the perimeter of a rectangle is 24 inches and the length is twice the width. What are the dimensions of this rectangle and what is the area?
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Question 309724: Suppose that the perimeter of a rectangle is 24 inches and the length is twice the width. What are the dimensions of this rectangle and what is the area? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! width =x
length = 2x
2x+2*2x=24
4x+2x=24
6x=24
x=4 inches
length = 8 inches
Area = L *W
8*4=32 square inches
