SOLUTION: The perimeter of a rectangle is 11 times its width. If the length of the rectangle is 54, find the width.
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Question 305460
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The perimeter of a rectangle is 11 times its width. If the length of the rectangle is 54, find the width.
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Let's length be L and width be w
Perimeter = 2L + 2w
L = 54
2(54) + 2w = 11w
108 = 9w
w = 108/ 9
w = 12
Width = 12