SOLUTION: the length of a rectangle is one less than twice the width. if the perimeter is 28 feet, find the dimensions

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Question 294158: the length of a rectangle is one less than twice the width. if the perimeter is 28 feet, find the dimensions
Answer by Deina(147) About Me  (Show Source):
You can put this solution on YOUR website!
Perimeter = 2w + 2l
l = 2w -1

substitute 2w - 1 for "l"
2w + 2(2w-1) = 28
2w + 4w - 2 = 28

combine like terms:
6w - 2 = 28

add 2 to each side:
+6w+-+cross%282+%2B2%29+=+cross%2828+%2B2%29+=+30+

Divide both sides by 6:
+6w%2F6+=+30%2F6+
w = 5

l = 2w - 1 so
l = 9
and bob's your uncle!