SOLUTION: The perimeter of a rectangle is 52 inches. If the length of the rectangle is 9 inches less than 4 times the width. Find the dimensions.

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is 52 inches. If the length of the rectangle is 9 inches less than 4 times the width. Find the dimensions.      Log On


   

Question 285627: The perimeter of a rectangle is 52 inches. If the length of the rectangle is 9 inches less than 4 times the width. Find the dimensions.
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
there are definetly similar problems to these in the rectangle section you should review that section before posting yours.
P=2%28L%2BW%29
L=4W-9
substitute and solve
P=2%28L%2BW%29
52=2%284W-9%2BW%29add
52=2%285W-9%29distribute
52=%2810W-18%29add
52%2B18=%2810W%29
70=10Wdivide
highlight%287=W%29
L=4W-9
L=4%287%29-9multiply
L=28-9subtract
highlight%28L=19%29