SOLUTION: How do you solve for the length and width of a rectangle that has a perimeter of 380 feet and the length is 70 feet less than 3 times the width?

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Question 280333: How do you solve for the length and width of a rectangle that has a perimeter of 380 feet and the length is 70 feet less than 3 times the width?
Found 2 solutions by vleith, pandion:
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
PerimeterOfRectangle+=+2%2ALength+%2B+2%2AWidth
Length+=+3%2AWidth+-+70
380+=+2%2A%283%2AWidth+-70%29+%2B+2%2AWidth
380+=+6%2AWidth+-+140+%2B2%2AWidth
520+=+8%2AWidth
65+=+Width
Length+=+3%2A65+-+70+=+125
Check answer.Does 2*125 +2*65 = 380???

Answer by pandion(6) About Me  (Show Source):
You can put this solution on YOUR website!
let x = L
y = W
P = 380
2x+%2B+2y+=+380+
x+=+3y+-+70
2%283y-70%29+%2B+2y+=+380
6y-140%2B2y+=+380
8y-140%2B140+=+380+%2B+140
8y%2F8=520%2F8
y=65