SOLUTION: 58. Geometry. The length of a rectangle is 2 in. more than twice its width. If them perimeter of the rectangle is 34 in., find the dimensions of the rectangle.

Algebra ->  Rectangles -> SOLUTION: 58. Geometry. The length of a rectangle is 2 in. more than twice its width. If them perimeter of the rectangle is 34 in., find the dimensions of the rectangle.      Log On


   



Question 27898: 58. Geometry. The length of a rectangle is 2 in. more than twice its width. If them perimeter of the rectangle is 34 in., find the dimensions of the rectangle.
Answer by zerosignal(28) About Me  (Show Source):
You can put this solution on YOUR website!
Given: length is 2 inches longer than twice its width, perimeter is 34 inches.
Let x = width (a)
Let 2x+2 = length (b)
perimeter+=+2a+%2B+2b
34+=+2x+%2B+2%282x%2B2%29
34+=+2x+%2B+4x+%2B+4
34+=+6x+%2B+4
30+=+6x
5+=+x
therefore, the width of the rectangle is 5inches, and the length is 2%2A%285%29%2B2+=+12inches.