SOLUTION: if the length of a rectangle is 3 feet greater than the width and it has an area of 28 square feet, what are its dimensions?

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Question 270911: if the length of a rectangle is 3 feet greater than the width and it has an area of 28 square feet, what are its dimensions?
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
L=W+3 and LW=28
then
%28W%2B3%29W=28
%28W%5E2%2B3W%29=28
W%5E2%2B3W-28=0 find 2 #'s that multiply together to get -28 and add together to get +3
%28W%2B7%29%28W-4%29
W=-7,4 since the area cant be negative, W=4
L=W+3
L=4%2B3
L=7