SOLUTION: Tiles are 1 -square inch. Made a retangular picture with 36 tiles. The length is 2 inches longer than the width. What are the dimensions of the picture?

Algebra ->  Rectangles -> SOLUTION: Tiles are 1 -square inch. Made a retangular picture with 36 tiles. The length is 2 inches longer than the width. What are the dimensions of the picture?       Log On


   

Question 268570: Tiles are 1 -square inch.
Made a retangular picture with 36 tiles.
The length is 2 inches longer than the width.
What are the dimensions of the picture?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Tiles are 1 -square inch.
Made a retangular picture with 36 tiles.
The length is 2 inches longer than the width.
What are the dimensions of the picture?
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Let width be "x" inches
Then length = "x+2" inches
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Area = x(x+2) = 36 sq in.
x^2+2x = 36
x^2 + 2x - 36 = 0
x = [-2 +- sqrt(4 - 4*1*-36)]/2
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x = [-2 +- sqrt(148)]/2
Positive solution:
x = [-2 + 2sqrt(37)]/2
x = -1 + sqrt(37) is approximately = 5.08 inches (width)
x + 2 is appoximately = 7.08 inches (length)
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Cheers,
Stan H.