SOLUTION: The perimeter of a rectangle is 26 m. The length is 1 m more than twice the width. Find the dimensions What I have so far P = 2 * L + 2 * W A = L * W 26=

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is 26 m. The length is 1 m more than twice the width. Find the dimensions What I have so far P = 2 * L + 2 * W A = L * W 26=       Log On


   

Question 251765: The perimeter of a rectangle is 26 m. The length is 1 m more than twice the width. Find the dimensions
What I have so far
P = 2 * L + 2 * W
A = L * W
26=
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Note: we're not asked to find the area, so we don't need the formula A=L*W


Since "The perimeter of a rectangle is 26 m", we know that 2L%2B2W=26. Also, since "The length is 1 m more than twice the width", we can say that L=2W%2B1



2L%2B2W=26 Start with the first equation.


2%282W%2B1%29%2B2W=26 Plug in L=2W%2B1


4W%2B2%2B2W=26 Distribute.


2%2B6W=26 Combine like terms on the left side.


6W=26-2 Subtract 2 from both sides.


6W=24 Combine like terms on the right side.


W=%2824%29%2F%286%29 Divide both sides by 6 to isolate W.


W=4 Reduce.


So the width is 4 meters.


L=2W%2B1 Now go back to the second equation


L=2%284%29%2B1 Plug in W=4


L=8%2B1 Multiply


L=9 Add


So the length is 9 meters.