SOLUTION: The length of a rectangle is three more than twice the width. The perimeter is 36 inches. Find the dimensions. I have x=2x +3 = 36 Have I done this correct.

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Question 224041: The length of a rectangle is three more than twice the width. The perimeter is 36 inches. Find the dimensions.
I have x=2x +3 = 36 Have I done this correct.
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is three more than twice the width. The perimeter is 36 inches. Find the dimensions.

Step 1. Perimeter means adding up the all 4 sides of the rectangle.

Step 2. Let w be the width.

Step 3. Let 2w+3 be the length.

Step 4. Then P=w+w+2w+3+2w+3=36 and solving yields the following steps.

Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: w=5.
  • Graphical form: Equation w%2Bw%2B2w%2B3%2B2w%2B3=36 was fully solved.
  • Text form: w+w+2w+3+2w+3=36 simplifies to 0=0
  • Cartoon (animation) form: simplify_cartoon%28+w%2Bw%2B2w%2B3%2B2w%2B3=36+%29
    For tutors: simplify_cartoon( w+w+2w+3+2w+3=36 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at w%2Bw%2B2%2Aw%2Bhighlight_red%28+3+%29%2B2%2Aw%2Bhighlight_red%28+3+%29=36.
Added fractions or integers together
It becomes w%2Bw%2B2%2Aw%2Bhighlight_green%28+6+%29%2B2%2Aw=36.
Look at w%2Bw%2B2%2Aw%2Bhighlight_red%28+6+%29%2B2%2Aw=36.
Moved 6 to the right of expression
It becomes w%2Bw%2B2%2Aw%2B2%2Aw%2Bhighlight_green%28+6+%29=36.
Look at .
Eliminated similar terms highlight_red%28+w+%29,highlight_red%28+w+%29,highlight_red%28+2%2Aw+%29,highlight_red%28+2%2Aw+%29 replacing them with highlight_green%28+%281%2B1%2B2%2B2%29%2Aw+%29
It becomes highlight_green%28+%281%2B1%2B2%2B2%29%2Aw+%29%2B6=36.
Look at .
Added fractions or integers together
It becomes %28highlight_green%28+6+%29%29%2Aw%2B6=36.
Look at highlight_red%28+%28highlight_red%28+6+%29%29%2Aw+%29%2B6=36.
Remove unneeded parentheses around factor highlight_red%28+6+%29
It becomes highlight_green%28+6+%29%2Aw%2B6=36.
Look at 6%2Aw%2B6=highlight_red%28+36+%29.
Moved these terms to the left highlight_green%28+-36+%29
It becomes 6%2Aw%2B6-highlight_green%28+36+%29=0.
Look at 6%2Aw%2Bhighlight_red%28+6+%29-highlight_red%28+36+%29=0.
Added fractions or integers together
It becomes 6%2Aw%2Bhighlight_green%28+-30+%29=0.
Look at 6%2Aw%2Bhighlight_red%28+-30+%29=0.
Removed extra sign in front of -30
It becomes 6%2Aw-highlight_green%28+30+%29=0.
Look at highlight_red%28+6%2Aw-30+%29=0.
Solved linear equation highlight_red%28+6%2Aw-30=0+%29 equivalent to 6*w-30 =0
It becomes highlight_green%28+0+%29=0.
Result: 0=0
This is an equation! Solutions: w=5.

Universal Simplifier and Solver


Done!



With w=5, then 2w+3=13 and P=2(5+13)=36 which is a true statement

Step 5. ANSWER: The dimensions of the rectangle are 5 inches and 13 inches.

I hope the above steps and explanation were helpful.

For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for
Trigonometry please visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.

Respectfully,
Dr J

http://www.FreedomUniversity.TV