SOLUTION: the perimeter of a rectangle is 140 m. The length is 4 m more than twice the width. Find the dimensions.

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Question 223628: the perimeter of a rectangle is 140 m. The length is 4 m more than twice the width. Find the dimensions.
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangle is 140 m. The length is 4 m more than twice the width. Find the dimensions.

Step 1. Perimeter P means adding up all 4 sides of a rectangle.

Step 2. Let w be the width.

Step 3. Let 2w+4 be the length since it's 4 more than twice the width

Step 4. Then, P=w+w+2w+4+2w+4=6w+8=140

Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: w=22.
  • Graphical form: Equation 6w%2B8=140 was fully solved.
  • Text form: 6w+8=140 simplifies to 0=0
  • Cartoon (animation) form: simplify_cartoon%28+6w%2B8=140+%29
    For tutors: simplify_cartoon( 6w+8=140 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at 6%2Aw%2B8=highlight_red%28+140+%29.
Moved these terms to the left highlight_green%28+-140+%29
It becomes 6%2Aw%2B8-highlight_green%28+140+%29=0.
Look at 6%2Aw%2Bhighlight_red%28+8+%29-highlight_red%28+140+%29=0.
Added fractions or integers together
It becomes 6%2Aw%2Bhighlight_green%28+-132+%29=0.
Look at 6%2Aw%2Bhighlight_red%28+-132+%29=0.
Removed extra sign in front of -132
It becomes 6%2Aw-highlight_green%28+132+%29=0.
Look at highlight_red%28+6%2Aw-132+%29=0.
Solved linear equation highlight_red%28+6%2Aw-132=0+%29 equivalent to 6*w-132 =0
It becomes highlight_green%28+0+%29=0.
Result: 0=0
This is an equation! Solutions: w=22.

Universal Simplifier and Solver


Done!



With w=22 and 2w%2B4=48. And P=2%2822%2B48%29=140 which is a true statement

Step 5. ANSWER: The width is 22 meters and the length is 48 meters.

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J