SOLUTION: The length of a rectangle is 6 cm more than the width. The area is 11 cm2. Find the length and width.

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Question 221224: The length of a rectangle is 6 cm more than the width. The area is 11 cm2. Find the length and width.
Answer by sofiyac(983) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is 6 cm more than the width. The area is 11 cm2. Find the length and width.
lets call width w, then length will be w+6 since area is 11 then
w(w+6)=11
w^2+6w-11=0
w+=+%28-6+%2B-+sqrt%28+6%5E2-4%2A1%2A%28-11%29+%29%29%2F%282%2A1%29+
w+=+%28-6+%2B-+sqrt%28+36%2B44+%29%29%2F2+
w+=+%28-6+%2B-+sqrt%28+80+%29%29%2F2+
w+=+%28-3+%2B-+4%2Asqrt%28+5+%29%29+ since our answer can't be negative because width can't be negative our answer would be
w+=+%28-3+%2B+4%2Asqrt%28+5+%29%29+ (about 5.9) and since length was 6 more than width
then length is
l+=+%28-3+%2B+4%2Asqrt%28+5+%29%29%2B6+=+%283+%2B+4%2Asqrt%28+5+%29%29+ (about 11.9)