SOLUTION: find the maximum area of a rectangle with a perimeter of 54 cenimeters

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Question 217813: find the maximum area of a rectangle with a perimeter of 54 cenimeters
Found 2 solutions by drj, rfer:
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
Find the maximum area of a rectangle with a perimeter of 54 centimeters.

Step 1. Perimeter P means adding up all 4 sides of a rectangle or P=w+w+L+L=2(w+L) where w is the width and L is the Length.

Step 2. Maximum Area A=w*L is when the rectangle is a square or A=s%5E2 where s=w=L.

Step 3. So P=2(w+L)=2(s+s)=4s.

Step 4. P=54=4s or s=54/4=13.5.

Step 5. A=s%5E2=13.5%5E2=182.25.

Step 6. ANSWER: Maximum area is 182.25 square centimeters.

I hope the above steps were helpful.

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Dr J
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Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
a square is always max.
54/4=13.5
A=lw
A=13.5*13.5
A=182.25 sq cm