SOLUTION: The perimeter of a rectangular field is 158 feet. If the length is 10 more than twice the width, find the length and the width.

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Question 217267: The perimeter of a rectangular field is 158 feet. If the length is 10 more than twice the width, find the length and the width.
Found 2 solutions by rfer, drj:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
2x+2(2x+10)=158
2x+4x+20=158
6x=138
x=23
2x+10=56

Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangular field is 158 feet. If the length is 10 more than twice the width, find the length and the width.

Step 1. Perimeter P is when adding up all the sides of the rectangular.

Step 2. Let w be the width.

Step 3. Let 2w be twice the width

Step 4. Let 2w+10 be the length since the length is 10 more than twice the width.

Step 5. Then P=w%2Bw%2B2w%2B10%2B2w%2B10=6w%2B20=158.

Step 6. Solving the equation in Step 5 yields

Subtract 20 from both sides of the equation

w%2Bw%2B2w%2B10%2B2w%2B20-20=6w%2B10=158-20

6w%2B20-20=158-20

6w=138

Divide 6 to both sides of the equation

6w%2F6=138%2F6

w=23

Then 2w%2B10=56

Check...P=2(23+56)=158...which is a true statement...

Step 7. ANSWER: The width is 23 feet and the length is 56 feet.

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J