SOLUTION: A rectangular rug has a length that is three feet longer than its width. Its area is 130 square feet. What are its dimensions. I know that the L is 13 and the Width has to be 10

Algebra ->  Rectangles -> SOLUTION: A rectangular rug has a length that is three feet longer than its width. Its area is 130 square feet. What are its dimensions. I know that the L is 13 and the Width has to be 10      Log On


   

Question 217208: A rectangular rug has a length that is three feet longer than its width. Its area is 130 square feet. What are its dimensions.
I know that the L is 13 and the Width has to be 10...but I don't know how to show it as a solved formula

Found 2 solutions by rfer, Earlsdon:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
lw+A
(w+3)(w)=130

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Try this! L = Length and W = Width.
L+=+W%2B3
Area: L*W = 130 Substitute L = W+3.
%28W%2B3%29%2AW+=+130
W%5E2%2B3W+=+130 Subtract 130 from both sides.
W%5E2%2B3W-130+=+0 Factor the trinomial.
%28W-10%29%28W%2B13%29+=+0
w-10+=+0 or W%2B13+=+0 so...
W+=+10 or W+=+-13 Discard the negative solution as width is a positive value.
highlight%28W+=+10%29 and:
L+=+W%2B3
highlight%28L+=+13%29