SOLUTION: A rectangle has an area of 62 square feet. Determine the perimeter, P, as a function of the width, w.

Algebra ->  Rectangles -> SOLUTION: A rectangle has an area of 62 square feet. Determine the perimeter, P, as a function of the width, w.      Log On


   



Question 214425: A rectangle has an area of 62 square feet. Determine the perimeter, P, as a function of the width, w.
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
A rectangle has an area of 62 square feet. Determine the perimeter, P, as a function of the width, w.

Step 1. The area A of a rectangle is 62 square feet=lw where l is the length and w is the width. So l=62/w

Step 2. Perimeter means adding up all the sides of a rectangle or P=l+l+w+w=2(l+w)

Step 3. Substitute l from Step 1 into Step 2 to yield, P=2*(62/w+w)=2*(62+w^2)/w

Step 4. Answer is P=2%2A%2862%2Bw%5E2%29%2Fw

I hope the above steps and explanation were helpful.

For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonmetry please visit http://www.FreedomUniversity.TV/courses/Trignometry.

Also, good luck in your studies and contact me at
john@e-liteworks.com for your future math needs.

Respectfully,
Dr J