SOLUTION: The width of a rectangle is 3 less than twice its length. If the area of the rectangle is 92 cm, what is the length of the diagonal?
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Question 214403: The width of a rectangle is 3 less than twice its length. If the area of the rectangle is 92 cm, what is the length of the diagonal? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! W=2L-3
WL=92
(2L-3)L=92
2L^2-3L-92=0
L=(3+-SQRT-3^2-4*2*-92])/2*2
L=(3+-SQRT[9+736])/4
L=(3+-SQRT745)/4
L=(3+-27.2947)/4
L=(3+27.2947)/4
L=30.2947/4
L=7.574 ANS. FOR THE LENGTH.
W=2*7.574-3
W=15.147-3
W=12.147 ANS. FOR THE WIDTH.
L^2+W^2=D^2
7.574^2+12.147^2=D^2
57.3655+147.5496=D^2
204.9151=D62
D=SQRT204.9151
D=14.315 ANS FOR THE DIAGONAL.
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