SOLUTION: The length of a rectangle is 6 cm more than 1 1/2 times the width. The perimiter of the rectangle is 56 cm. Find the dimensions of the rectangle.Can someone show me the work too?

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 6 cm more than 1 1/2 times the width. The perimiter of the rectangle is 56 cm. Find the dimensions of the rectangle.Can someone show me the work too?      Log On


   

Question 206503: The length of a rectangle is 6 cm more than 1 1/2 times the width. The perimiter of the rectangle is 56 cm. Find the dimensions of the rectangle.Can someone show me the work too?
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
width=x=8.8
length=1.5x+6=19.2
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P=2L+2W
2(1.5x+6)+2x=56
3x+12+2x=56
subtract 12 from both sides.
5x=56-12
5x=44
x=8.8
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P=2(8.8)+2(19.2)=56