SOLUTION: I am trying to find the length of a rectangle in terms of x. the width of the rectangle is 4x + 3 and the area of the rectangle ix 4x^3-5x^2-10x-3. Please help

Algebra ->  Rectangles -> SOLUTION: I am trying to find the length of a rectangle in terms of x. the width of the rectangle is 4x + 3 and the area of the rectangle ix 4x^3-5x^2-10x-3. Please help      Log On


   



Question 195423: I am trying to find the length of a rectangle in terms of x.
the width of the rectangle is 4x + 3
and the area of the rectangle ix 4x^3-5x^2-10x-3.
Please help

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
You know that Area of rectangle is given by
Area+=+Length+%2A+Width
So
4x%5E3-5x%5E2-10x-3+=+Length+%2A+%284x%2B3%29
%284x%5E3-5x%5E2-10x-3%29%2F%284x%2B3%29+=+Length
Use this URL to solve for length --> http://www.calc101.com/webMathematica/long-divide.jsp