Question 192108: the width of the rectangle is 5 feet and the diagonal is 9 feet. what is the area of the rectangle? Answer by RAY100(1637) (Show Source):
You can put this solution on YOUR website! drawing a picture shows a rectangle (l*w) with diagonal
given diag = 9, and width=5
using pythagorous
a^2+b^2=c^2
l^2+5^2=9^2
l^2 +25 =81
subt 25 both sides
l^2 = 56
take sq rt both sides
l=7.483
area is L*W= 7.483 *5=37.417
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