SOLUTION: The length of a rectangle is 3 feet longer than the width. The permineter is 30 feet. Find the dimensions of the rectangle. a. length = 8 feet; width = 5 feet b. length = 8 feet;

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 3 feet longer than the width. The permineter is 30 feet. Find the dimensions of the rectangle. a. length = 8 feet; width = 5 feet b. length = 8 feet;      Log On


   

Question 190102This question is from textbook Beginning & Intermediate Algebra
: The length of a rectangle is 3 feet longer than the width. The permineter is 30 feet. Find the dimensions of the rectangle.
a. length = 8 feet; width = 5 feet
b. length = 8 feet; width = 7 feet
c. length = 9 feet; width = 6 feet This question is from textbook Beginning & Intermediate Algebra

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
P=2L+2w
.
L=w+3
2(w+3)+2w=30 Substitute w+3 for L
2w+6+2w=30
4w=24
w=6
L=9
.
Ed