SOLUTION: A rectangular yard is surrounded by a fence that is 4 feet longer than it is wide. If the perimeter of the fence is 424 feet, what are the dimensions of the yard it encloses?

Algebra ->  Rectangles -> SOLUTION: A rectangular yard is surrounded by a fence that is 4 feet longer than it is wide. If the perimeter of the fence is 424 feet, what are the dimensions of the yard it encloses?      Log On


   



Question 1768: A rectangular yard is surrounded by a fence that is 4 feet longer than it is wide. If the perimeter of the fence is 424 feet, what are the dimensions of the yard it encloses?
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
let one length of the yard be x. The other is then (x+4), seeing as how it is 4 feet longer.
the perimeter is then just the addition of all 4 lengths and that adds up to 424, so:
x+%2B+%28x%2B4%29+%2B+x+%2B+%28x%2B4%29+=+424
4x+%2B+8+=+424
4x+=+416
x+=+104
So, the other length is 108.
Check... 104+108+104+108 is 424. Therefore, a correct answer :-)
cheers
Jon.