SOLUTION: The length of a rectangle is 3 more than twice the width. The area is 44 square feet. Find the dimensions of the rectangle.

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Question 172459: The length of a rectangle is 3 more than twice the width. The area is 44 square feet. Find the dimensions of the rectangle.
Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
L=3%2B2W
W=W
A=44ft%5E2
Then,
A=L%2AW ------>44ft%5E2=%283%2B2W%29%28W%29
44=3W%2B2W%5E2 ----------->2W%5E2%2B3W-44=0
By Quadratic: x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
where--->system%28a=2%2Cb=3%2Cc=-44%29
Plug in the values and you'll get:
x=highlight%284ft=W%29 ---->Width; x=-22%2F4, disregard
Also, L=3%2B2%2A4=3%2B8=highlight%2811=L%29
Check,
44=11%2A4
44ft%5E2=44ft%5E2
Thank you,
Jojo