SOLUTION: The length of a rectangle is increased by 60%. By what % would the width have to be decreased to maintain the same area?
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Question 169670: The length of a rectangle is increased by 60%. By what % would the width have to be decreased to maintain the same area? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The length of a rectangle is increased by 60%. By what % would the width have to be decreased to maintain the same area?
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Assume the original area = LW
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EQUATION after the change:
Let the new width be "x".
(1.6L)x = LW
1.6x = W
x = 0.625W
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The width would have to be increased by 62.5%
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Cheers,
Stan H.
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