SOLUTION: Suppose you built all the rectangles possible from 48 square tiles. Which rectangle would have the largest perimeter? Which would have the smallest perimeter?
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-> SOLUTION: Suppose you built all the rectangles possible from 48 square tiles. Which rectangle would have the largest perimeter? Which would have the smallest perimeter?
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Question 167505: Suppose you built all the rectangles possible from 48 square tiles. Which rectangle would have the largest perimeter? Which would have the smallest perimeter? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! 2L+2W=PERIMETER.
L*W=48
1 BY 48=2*1+2*48=2+96=98 FOR THE LONGEST PERIMETER.
2 BY 24=2*2+2*24=4+48=52
3 BY 16=2*3+2*16=6+32=38
4 BY 12=2*4+2*12=8+24=32
6 BY 8=2*6+2*8=12+16=28 FOR THE SHORTEST PERIMETER.
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