SOLUTION: A rectangle has a area of X^3-6X^2+15X-28 square feet. Its width is X-4 feet. What is its length?

Algebra ->  Rectangles -> SOLUTION: A rectangle has a area of X^3-6X^2+15X-28 square feet. Its width is X-4 feet. What is its length?      Log On


   

Question 146123: A rectangle has a area of X^3-6X^2+15X-28 square feet. Its width is X-4 feet. What is its length?
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
A=L*w
L=A/w
(x^3-6x^+15x-28)/(x-4) Use long division or synthetic division.
=x^2-2x+7 Ans.
.
Ed