SOLUTION: You have 172 feet of fencing to enclose a rectangular region. Find the dimensions of the rectangle that maximize the enclosed area. possible answers: D, 43 by 43 is the max. So

Algebra ->  Rectangles -> SOLUTION: You have 172 feet of fencing to enclose a rectangular region. Find the dimensions of the rectangle that maximize the enclosed area. possible answers: D, 43 by 43 is the max. So      Log On


   



Question 144235: You have 172 feet of fencing to enclose a rectangular region. Find the dimensions of the rectangle that maximize the enclosed area.
possible answers: D, 43 by 43 is the max.
Solution: The area the product of 2 sides. Since it's a rectangle, 2 adjacent sides will use 1/2 of the 172 feet, or 86 feet.
The area = L x (86-L), or 86L-L%5E2
Set the 1st derivative = 0.
86-2L=0 (Yes, it's a calculus problem any time you want max or minimum.)
86 = 2L
L = 43.
A) 45ft by 41ft B) 86ft by 21.5ft
C) 86ft by 86ft D) 43ft by 43ft

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