SOLUTION: Please help, I can't remember the steps to solve this problem. The width of a rectangle is 4 ft less than the length. The area is 5 ft^2. What is the length and width.

Algebra ->  Rectangles -> SOLUTION: Please help, I can't remember the steps to solve this problem. The width of a rectangle is 4 ft less than the length. The area is 5 ft^2. What is the length and width.      Log On


   



Question 143005: Please help, I can't remember the steps to solve this problem. The width of a rectangle is 4 ft less than the length. The area is 5 ft^2. What is the length and width.
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
The width aof a rectangle is 4+ft+less than the length b.
Means: b+=+a+%2B+4ft
The area A is 5+ft%5E2.
To find:
What is the length and width?
A+=+a%2Ab
A+=+a%2A%28+a+%2B+4ft+%29
5+ft%5E2+=+a%2A%28+a+%2B+4ft+%29
5+ft%5E2+=+a%5E2+%2B+a%2A4ft+
a%5E2+%2B+a%2A4ft+-+5+ft%5E2=0+…..use quadratic formula to find a

a+=+%28-4%2B-+sqrt%28+4%5E2-4%2A1%2A-5%29+%29%29%2F%282%2A1%29+
a+=+%28-4%2B-+sqrt%28+16+%2B+20%29%29+%2F2+
a+=+%28-4%2B-+sqrt%28+36%29%29+%2F2+
a+=+%28-4%2B-+%28+6%29%29+%2F2+
a+=+%28-4%2B6%29+%2F2+
a+=+2+%2F2+
highlight%28a+=+1ft%29+…………
b+=+a+%2B+4ft
b+=+1ft+%2B+4ft
+highlight+%28b+=+5ft%29