SOLUTION: I am a rectangular picture frame.if I were straight.I would be 120 inches long.I am wrapped around a picture.and my length is twice as long as my width.what is the area of the pict

Algebra ->  Rectangles -> SOLUTION: I am a rectangular picture frame.if I were straight.I would be 120 inches long.I am wrapped around a picture.and my length is twice as long as my width.what is the area of the pict      Log On


   

Question 1158609: I am a rectangular picture frame.if I were straight.I would be 120 inches long.I am wrapped around a picture.and my length is twice as long as my width.what is the area of the picture that I am wrapped around.
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

I am a rectangular picture frame.if I were straight.I would be 120 inches long.

=> perimeter is
P=2%28L%2BW%29=120in........eq.1
I am wrapped around a picture and my length is twice as long as my width
L=2W.......eq.2
first find dimensions:
2%28L%2BW%29=120in
L%2BW=60in........substitute in L=2W
2W%2BW=60in
3W=60in
W=20in

substitute back in L=2W
L=2%2A20in
L=40in
the area of the picture that I am wrapped around is:
A=L%2AW
A=40in%2A20in
A=800in%5E2