SOLUTION: A rectangular field beside a river is to be fenced by 80 meters of fencing. No fence is needed along the riverbank. What are the dimensions of the field that maximize its area?
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Question 1157514: A rectangular field beside a river is to be fenced by 80 meters of fencing. No fence is needed along the riverbank. What are the dimensions of the field that maximize its area? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
Since one side is the river, the rectangle's fence perimeter will be
L + 2W = 80.
Hence, L = 80 - 2W.
Area = Length * Width.
Substitute (80-2W) for L:
A = W(80 - 2W)
A = -2W^2 + 80W.
This is a quadratic function. It has the maximum at x = -b/(2a), according to the general theory.
(See the lessons
- HOW TO complete the square to find the minimum/maximum of a quadratic function
- Briefly on finding the minimum/maximum of a quadratic function
in this site).
For our quadratic function the maximum is at
W = = = 20.
So, W = 20 meters is the width for max area.
Then the length is L = 80 - 2W = 80 - 2*20 = 40 meters
Find the max area. Substitute 20 for W
A = -2(20^2) + 80*20 = 800 square meters.
The plot of the quadratic function for the area is shown below: y = area and x = width.