SOLUTION: A rectangular field beside a river is to be fenced by 80 meters of fencing. No fence is needed along the riverbank. What are the dimensions of the field that maximize its area?

Algebra ->  Rectangles -> SOLUTION: A rectangular field beside a river is to be fenced by 80 meters of fencing. No fence is needed along the riverbank. What are the dimensions of the field that maximize its area?      Log On


   



Question 1157514: A rectangular field beside a river is to be fenced by 80 meters of fencing. No fence is needed along the riverbank. What are the dimensions of the field that maximize its area?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x, x, 80-2x
The three lengths
80-2x is length parallel to riverbank

x%2880-2x%29, area

Maximum area should be in exact middle between the zeros.
One zero is 0.
Other zero is 80-2x=0
40-x=0
x=40

Exact middle of 0 and 40 is 20.

Dimensions to max area:
20 and 40.

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

Since one side is the river, the rectangle's fence perimeter will be
L + 2W = 80.

Hence, L = 80 - 2W.

Area = Length * Width.

Substitute (80-2W) for L:

    A = W(80 - 2W)

    A = -2W^2 + 80W.

This is a quadratic function. It has the maximum at x = -b/(2a), according to the general theory.

    (See the lessons
     
         - HOW TO complete the square to find the minimum/maximum of a quadratic function

         - Briefly on finding the minimum/maximum of a quadratic function

     in this site).


For our quadratic function the maximum is at

    W = -80%2F%282%2A%28-2%29%29 = %28-80%29%2F%28-4%29 = 20.

So, W = 20 meters is the width for max area.

Then the length is  L = 80 - 2W = 80 - 2*20 = 40 meters

Find the max area. Substitute 20 for W

    A = -2(20^2) + 80*20 = 800 square meters.

The plot of the quadratic function for the area is shown below:  y = area and x = width.

+graph%28+300%2C+200%2C+-50%2C+50%2C+-100%2C+1000%2C+-2x%5E2+%2B+80x%29+ 


My other lessons in this site on finding the maximum/minimum of a quadratic function are
    - HOW TO complete the square to find the minimum/maximum of a quadratic function
    - Briefly on finding the minimum/maximum of a quadratic function
    - HOW TO complete the square to find the vertex of a parabola
    - Briefly on finding the vertex of a parabola
    - A rectangle with a given perimeter which has the maximal area is a square
    - A farmer planning to fence a rectangular garden to enclose the maximal area
    - A rancher planning to fence two adjacent rectangular corrals to enclose the maximal area
    - Finding the maximum area of the window of a special form
    - Using quadratic functions to solve problems on maximizing revenue/profit
    - Minimal distance between sailing ships in a sea
    - Advanced lesson on finding minima of (x+1)(x+2)(x+3)(x+4)
    - OVERVIEW of lessons on finding the maximum/minimum of a quadratic function

Use this file/link  ALGEBRA-I - YOUR ONLINE TEXTBOOK  to navigate over all topics and lessons of the online textbook  ALGEBRA-I.