SOLUTION: Casey wants to shrink a poster at Kinko’s. The poster is two feet by three feet. He wants to make it 1/9 of the area of the original poster. What will be the dimensions in inch

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Question 1157114: Casey wants to shrink a poster at Kinko’s. The poster is two feet by three feet. He wants to make it 1/9 of the
area of the original poster. What will be the dimensions in inches of the new poster?
Found 2 solutions by josmiceli, MathTherapy:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I want the proportions to stay the same, so
I will say:
+%28+2%2Ak+%29%2A%28+3%2Ak+%29+=+%28+1%2F9+%29%2A%28+2%2A3+%29+
+6k%5E2+=+6%2A%28+1%2F9+%29+
+k%5E2+=+1%2F9+
+k+=+1%2F3+
--------------------
The new dimensions are:
+%28+2k+%29%2A%28+3k+%29+=+2%2A%281%2F3%29+%2A+3%2A%28+1%2F3+%29+
+%28+2k+%29%2A%28+3k+%29+=+2%2F3+%2A+1+
------------------------------
2/3 ft x 1 ft
----------------
check:
+%282%2F3%29%2A1+=+%28+1%2F9%29%2A2%2A3+
+2%2F3+=+6%2F9+
+2%2F3+=+2%2F3+
OK
get a 2nd opinion if needed

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Casey wants to shrink a poster at Kinko’s. The poster is two feet by three feet. He wants to make it 1/9 of the area of the original poster. What will be the dimensions in inches of the new poster?
Original dimensions of poster: 2' x 3', or 24" x 36"

Shrinking ORIGINAL AREA by 1%2F9 MEANS shrinking the DIMENSIONS by sqrt%281%2F9%29, or by 1%2F3.

Shrinkage results in ORIGINAL DIMENSIONS of