SOLUTION: The length of a rectangle is 7 inches longer than it is wide. If the perimeter is 38 inches, what are the dimensions of the rectangle?

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Question 1156639: The length of a rectangle is 7 inches longer than it is wide. If the perimeter is 38 inches, what are the dimensions of the rectangle?
Found 3 solutions by josgarithmetic, MathLover1, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
w%2B%28w%2B7%29=38%2F2
2w=19-7=12
w=6

system%2813%2Cand%2C6%29--------dimensions

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

if the length L of a rectangle is 7 inches longer than it is wide W, we have
L=W%2B7.....eq.1

if the perimeter is 38 inches, we have
2%28L%2BW%29=38
L%2BW=38%2F2
L%2BW=19......substitute L from eq.1
W%2B7%2BW=19
2W=19-7
2W=12
W=6
go to
L=W%2B7.....eq.1, ....substitute W
L=6%2B7
L=13

the dimensions of the rectangle are 13 by 6


Answer by ikleyn(52779) About Me  (Show Source):
You can put this solution on YOUR website!
.

            The solution by @josgarithmetic is TOTALLY WRONG.

            For your safety, simply ignore it.

            The correct solution is THIS 


W + (W+7) = 38/2 = 19


2W = 19-7 = 12.

W         = 12/2 = 6.


ANSWER.  The dimensions are  6 and 13 inches.

Solved.

-----------------

So called "tutor" @josgarithmetic deceives you every day and every time,
from year to year.


The only way is to post (to Email) to the owner of this site Igor Chudov,
asking him to exclude this person from the pool of tutors.