SOLUTION: The diagonals of a parallelogram intersect at (−1,3). One of the sides of the parallelogram is bounded by (0,6) and (3,1). Graph the parallelogram on your paper and fin

Algebra ->  Rectangles -> SOLUTION: The diagonals of a parallelogram intersect at (−1,3). One of the sides of the parallelogram is bounded by (0,6) and (3,1). Graph the parallelogram on your paper and fin      Log On


   



Question 1135008: The diagonals of a parallelogram intersect at (−1,3). One of the sides of the
parallelogram is bounded by (0,6) and (3,1).
Graph the parallelogram on your paper and find the coordinates of the remaining
vertices.

[] (−5,5)
[] (−4,0)
[] (−2,2)
[] (−2,0)
[] (−5,3)
[] (0,0)
[] (−7,5)

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
The diagonals of a parallelogram intersect at (−1,3). One of the sides of the
parallelogram is bounded by (0,6) and (3,1).
Graph the parallelogram on your paper and find the coordinates of the remaining
vertices.
plot the given points and draw the side of the parallelogram

Draw in the two half-diagonals:

To go from (0,6) to (-1,3), you have to go 
1 unit left and 3 units down. So to get the
complete diagonal, start at (-1,3) and do the
same thing. That is go 1 unit left and 3 
units down, like below and you end up at (-2,0):

Similarly to go from (3,1) to (-1,3), you have to go 
4 units left and 2 units up. So to get the
complete diagonal, start at (-1,3) and do the
same thing. That is go 4 units left and 2 
units up, like below and you end up at (-5,5):

Now you can draw in the complete parallelogram:

Edwin