SOLUTION: The length of the rectangle exceeds its breadth by 3 cm. If the length and breadth are each increased by 2 cm, then the area of new rectangle will be 70 sq. cm more than that of th

Algebra ->  Rectangles -> SOLUTION: The length of the rectangle exceeds its breadth by 3 cm. If the length and breadth are each increased by 2 cm, then the area of new rectangle will be 70 sq. cm more than that of th      Log On


   

Question 1111211: The length of the rectangle exceeds its breadth by 3 cm. If the length and breadth are each increased by 2 cm, then the area of new rectangle will be 70 sq. cm more than that of the given rectangle. Find the length and breadth of the given rectangle.
Answer by ikleyn(52780) About Me  (Show Source):
You can put this solution on YOUR website!
.
One equation is 

L - W = 3     (1)        ("The length of the rectangle exceeds its breadth by 3 cm.")


The second equation is 

(L+2)*(W+2) - LW = 70,   ("If the length and breadth are each increased by 2 cm, then the area of new rectangle . . . ")  

or, after simplifying

L + W = 33     (2) 


So, you have the system of two equations in two unknowns (1),(2). By solving it,  you get

L = 18 cm,  W = 15 cm.


Check.  (18+2)*(15+2) - 18*15 = 70 sq cm.   ! Correct !

Solved.

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To see other similar solved problems, see the lessons
    - Problems on the area and the dimensions of a rectangle surrounded by a strip
    - Problems on a circular pool and a walkway around it
in this site.