SOLUTION: The perimeter of a rectangle is 52 feet. The length is 2 feet more than 5 times the width. Find the dimensions of the rectangle.

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is 52 feet. The length is 2 feet more than 5 times the width. Find the dimensions of the rectangle.       Log On


   

Question 1103214: The perimeter of a rectangle is 52 feet. The length is 2 feet more than 5 times the width. Find the dimensions of the rectangle.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
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The perimeter of a rectangle is 52 feet.
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p=52
L, length
w, width
p=2w+2L

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The length is 2 feet more than 5 times the width.
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L=5w+2


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Find the dimensions of the rectangle.
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Do that. All the basic starting data is ready. Just a couple of substitutions and a few simple algebra steps.