SOLUTION: 1. A picture 6 dm more than its width is to be framed with 3 dm border. The total area of the border is 288 square dm. What are the dimensions of the pictures?
2. The area of a 12
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-> SOLUTION: 1. A picture 6 dm more than its width is to be framed with 3 dm border. The total area of the border is 288 square dm. What are the dimensions of the pictures?
2. The area of a 12
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Question 1096264: 1. A picture 6 dm more than its width is to be framed with 3 dm border. The total area of the border is 288 square dm. What are the dimensions of the pictures?
2. The area of a 12mx8m rectangle is to be doubled. By what equal amount must each dimensions be increased?
3. The product of two consecutive integers is 210. What are the numbers Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! 1.Let w and w+6 be the width and the length of the picture, respectively. Then, the frame would be w+6 by w+12. So:
(w+6)(w+12)-(w)(w+6)=288
Solve for w
2. Let n be the amount that both dimensions need to be increased. Then:
(12+w)(8+w)=2(12)(8)=192
w²+20w+96=192
w²+20w-96=0
Solve for w
3.Let n be the first integer. Then, the second would be n+1. So:
n(n+1)=210
n²+n-210=0
Solve for n
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