SOLUTION: the area of the rectangle shown below is 2(3x-2)/x-1. find the width. 2x+6/12x-15 is the length of the rectangle.

Algebra ->  Rectangles -> SOLUTION: the area of the rectangle shown below is 2(3x-2)/x-1. find the width. 2x+6/12x-15 is the length of the rectangle.      Log On


   

Question 109414: the area of the rectangle shown below is 2(3x-2)/x-1. find the width. 2x+6/12x-15 is the length of the rectangle.
Answer by chitra(359) About Me  (Show Source):
You can put this solution on YOUR website!
It is given that the area of the rectangle is 2%283x+-+2%29%2F%28x+-+1%29+

the length is = %282x+%2B+6%29%2F%2812x+-+15%29

We are supposed to find the width of the rectangle.

We know that the area of the rectangle is given by A = l * w

So substituing for the values, we get:

2%283x+-+2%29%2F%28x+-+1%29+=+%282x+%2B+6%29%2F%2812x+-+15%29+%2A+w+

therfore w = A/l

w = +%282%283x+-+2%29%2F%28x+-+1%29%29%2F+%28%282x+%2B+6%29%2F%2812x+-+15%29%29+


Therfore w = %282%283x+-+2%29%2F%28x+-+1%29%29+%2A+%28%2812x+-+15%29%2F%282x+%2B+6%29%29+


This can be written as:

w = 3((3x - 2)(4x - 5))/((x - 1)(x + 3))}}}

Thus the solution.