SOLUTION: perimeter of the playing field is 342. the length is 3 less than double the width. What are the dimensions

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Question 1093787: perimeter of the playing field is 342. the length is 3 less than double the width. What are the dimensions
Found 2 solutions by josgarithmetic, josmiceli:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Dimensions are 2w-3 and w so given perimeter would follow 2%282w-3%29%2B2w=342.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +w+ = the width
+2w+-+3+ = the length
Let +P+ = the perimeter
+P+=+2w+%2B+2%2A%28+2w+-+3+%29+
+342+=+2w+%2B+4w+-+6+
+6w+=+348+
+w+=+58+
and
+2w+-+3+=+113+
The field is 58 x 113
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check:
+P+=+2%2A58+%2B+2%2A113+
+342+=+116+%2B+226+
+342+=+342+
OK